Python - Check if a given string is binary string or not (2024)

In this article we check if a given string has characters which are only 1 or 0. We call such strings as binary strings. If it has any other digit like 2 or 3 etc., we classify it as a non-binary string.

With set

The set operator in python stores only unique elements. So we take a string and apply the set function to it. Then we create another set which has only 0 and 1 as its elements. If both these sets are equal then the string is definitely binary. Also the string may have only 1s or only 0s. So we create a or condition which will also compare the result of set operator only with 0 or only with 1.

Example

Live Demo

stringA = '0110101010111'b = {'0','1'}t = set(stringA)if b == t or t == {'0'} or t == {'1'}:print("StringA is a binary string.")else:print("StringA is not a binary string.")stringB = '0120101010111'u = set(stringB)if b == u or u == {'0'} or u == {'1'}:print("StringB is a binary string.")else:print("StringB is not a binary string.")

Output

Running the above code gives us the following result −

StringA is a binary string.StringB is not a binary string.

With simple iteration

We can first declare a string with value as 01 or 10. Then compare the chraracters of this string with the characters of the given string. If the

Example

Live Demo

stringA = "01100000001"b = '10'count = 0for char in stringA: if char not in b: count = 1 break else: passif count: print("StringA is not a binary string")else: print("StringA is a binary string")stringB = "01200000001"for char in stringB: if char not in b: count = 1 break else: passif count: print("StringB is not a binary string")else: print("StringB is a binary string")

Output

Running the above code gives us the following result −

StringA is a binary stringStringB is not a binary string