HCF of 20 and 48 - Methods, Solved Examples & FAQs (2024)

FAQs

HCF of 20 and 48 - Methods, Solved Examples & FAQs? ›

In the prime factorisation method, we can express the given numbers as the product of prime factors. Therefore the numbers 20 and 48 can be expressed as: 20 = 2 × 2 × 5, 48 = 2 × 2 × 2 × 2 × 3. Common prime factors of 20 and 48 are 2 and 2. Therefore, HCF (20, 48) = 2 × 2 = 4.

The HCF of 20 and 48 is 4. To calculate the HCF of 20 and 48, we need to factor each number (factors of 20 = 1, 2, 4, 5, 10, 20; factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48) and choose the highest factor that exactly divides both 20 and 48, i.e., 4.

HCF can be evaluated for two or more than two numbers. It is the greatest divisor for any two or more numbers, that can equally or completely divide the given numbers. For Example: The Highest common factor of 60 and 75 is 15 because 15 is the largest number which can divide both 60 and 75 exactly.

Answer. The HCF of the given numbers 20, 32, and 48 by long division method is 8.

The lcm of 20 and 48 is 240.

This HCF of 20, 48 and 72 will be 4.

Step 1: Divide the largest number by the smallest number. Step 2: Take divisor as new dividend and remainder as the new divisor, i.e. divide the first divisor by the first remainder. Step 3: Proceed till the remainder is zero and the last divisor will be the HCF of the given numbers.

Step 1: Find the prime factorization of each number. Step 2: Find the common prime factors of those numbers. Step 3: Find the HCF of those numbers by finding the product of the prime factors with the lowest exponential power or factors that are common to each of the given numbers.

Factors of 48 by Division Method

Thus, the factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48. If we divide 48 by any numbers other than 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48, it leaves a remainder, and hence, they are not the factors of 48.

First, divide the large number by a small number. If the remainder is left, then divide the first divisor by remainder. If the remainder divides the first divisor completely, then it is the HCF or highest common factor of the given two numbers.

What are the rules for finding HCF? ›

The highest common factor is found by multiplying all the factors which appear in both lists: So the HCF of 60 and 72 is 2 × 2 × 3 which is 12. The lowest common multiple is found by multiplying all the factors which appear in either list: So the LCM of 60 and 72 is 2 × 2 × 2 × 3 × 3 × 5 which is 360.

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48. There are 6 common factors of 36 and 48, i.e. 1, 2, 3, 4, 6 and 12. Therefore, the highest common factor of 36 and 48 is 12.

The LCM of 20 and 40 is 40 and the HCF of 20 and 40 is 20.

The greatest common factor of 20 and 45 is 5.

The H.C.F of 44 and 20 is 7.